How to Convert Btu (IT) per Pound °F to Joule per Kilogram Kelvin
To convert Btu (IT) per Pound °F to Joule per Kilogram Kelvin, multiply the value in Btu (IT) per Pound °F by the conversion factor 4,186.80000001.
1 Btu (IT) per Pound °F × 4,186.800000 = 4,186.8000 Joule per Kilogram Kelvin
Btu (IT) per Pound °F to Joule per Kilogram Kelvin Conversion Table
| Btu (IT) per Pound °F | Joule per Kilogram Kelvin |
|---|---|
| 0.01 | 41.8680 |
| 0.1 | 418.6800 |
| 1 | 4,186.8000 |
| 2 | 8,373.6000 |
| 3 | 12,560.4000 |
| 5 | 20,934.0000 |
| 10 | 41,868.0000 |
| 20 | 83,736.0000 |
| 50 | 209,340.0000 |
| 100 | 418,680.0000 |
| 1000 | 4.1868E+6 |