Joule per Kilogram °C Calorie (IT) per Gram °F

Convert Joule per Kilogram °C to Calorie (IT) per Gram °F with precision
1 Joule per Kilogram °C = 0.000239 Calorie (IT) per Gram °F

Quick Answer: 1 Joule per Kilogram °C is equal to 0.000238845896627 Calorie (IT) per Gram °F.

How to Convert Joule per Kilogram °C to Calorie (IT) per Gram °F

To convert Joule per Kilogram °C to Calorie (IT) per Gram °F, multiply the value in Joule per Kilogram °C by the conversion factor 0.00023885.

Conversion Formula
1 Joule per Kilogram °C × 0.000239 = 0.0002 Calorie (IT) per Gram °F

Joule per Kilogram °C to Calorie (IT) per Gram °F Conversion Table

Joule per Kilogram °C Calorie (IT) per Gram °F
0.01 2.3885E-6
0.1 2.3885E-5
1 0.0002
2 0.0005
3 0.0007
5 0.0012
10 0.0024
20 0.0048
50 0.0119
100 0.0239
1000 0.2388

Complete list of Joule per Kilogram °C for conversion

Joule per Kilogram °C → Joule per Kilogram Kelvin J/(kg·°C) → J/(kg·K) Joule per Kilogram Kelvin → Joule per Kilogram °C J/(kg·K) → J/(kg·°C) Joule per Kilogram °C → Joule per Gram °C J/(kg·°C) → J/(g·°C) Joule per Gram °C → Joule per Kilogram °C J/(g·°C) → J/(kg·°C) Joule per Kilogram °C → Kilojoule per Kilogram Kelvin J/(kg·°C) → kJ/(kg·K) Kilojoule per Kilogram Kelvin → Joule per Kilogram °C kJ/(kg·K) → J/(kg·°C) Joule per Kilogram °C → Kilojoule per Kilogram °C J/(kg·°C) → kJ/(kg·°C) Kilojoule per Kilogram °C → Joule per Kilogram °C kJ/(kg·°C) → J/(kg·°C) Joule per Kilogram °C → Calorie (IT) per Gram °C J/(kg·°C) → cal(IT)/(g·°C) Calorie (IT) per Gram °C → Joule per Kilogram °C cal(IT)/(g·°C) → J/(kg·°C) Joule per Kilogram °C → Calorie (IT) per Gram °F J/(kg·°C) → cal(IT)/(g·°F) Calorie (IT) per Gram °F → Joule per Kilogram °C cal(IT)/(g·°F) → J/(kg·°C) Joule per Kilogram °C → Calorie (th) per Gram °C J/(kg·°C) → cal(th)/(g·°C) Calorie (th) per Gram °C → Joule per Kilogram °C cal(th)/(g·°C) → J/(kg·°C) Joule per Kilogram °C → Kilocalorie (IT) per Kilogram °C J/(kg·°C) → kcal(IT)/(kg·°C) Kilocalorie (IT) per Kilogram °C → Joule per Kilogram °C kcal(IT)/(kg·°C) → J/(kg·°C) Joule per Kilogram °C → Kilocalorie (th) per Kilogram °C J/(kg·°C) → kcal(th)/(kg·°C) Kilocalorie (th) per Kilogram °C → Joule per Kilogram °C kcal(th)/(kg·°C) → J/(kg·°C)
Joule per Kilogram °C → Kilocalorie (IT) per Kilogram Kelvin J/(kg·°C) → kcal(IT)/(kg·K) Kilocalorie (IT) per Kilogram Kelvin → Joule per Kilogram °C kcal(IT)/(kg·K) → J/(kg·°C) Joule per Kilogram °C → Kilocalorie (th) per Kilogram Kelvin J/(kg·°C) → kcal(th)/(kg·K) Kilocalorie (th) per Kilogram Kelvin → Joule per Kilogram °C kcal(th)/(kg·K) → J/(kg·°C) Joule per Kilogram °C → Kilogram-force Meter per Kg K J/(kg·°C) → kgf·m/(kg·K) Kilogram-force Meter per Kg K → Joule per Kilogram °C kgf·m/(kg·K) → J/(kg·°C) Joule per Kilogram °C → Pound-force Foot per Pound °R J/(kg·°C) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Joule per Kilogram °C lbf·ft/(lb·°R) → J/(kg·°C) Joule per Kilogram °C → Btu (IT) per Pound °F J/(kg·°C) → Btu(IT)/(lb·°F) Btu (IT) per Pound °F → Joule per Kilogram °C Btu(IT)/(lb·°F) → J/(kg·°C) Joule per Kilogram °C → Btu (th) per Pound °F J/(kg·°C) → Btu(th)/(lb·°F) Btu (th) per Pound °F → Joule per Kilogram °C Btu(th)/(lb·°F) → J/(kg·°C) Joule per Kilogram °C → Btu (IT) per Pound °R J/(kg·°C) → Btu(IT)/(lb·°R) Btu (IT) per Pound °R → Joule per Kilogram °C Btu(IT)/(lb·°R) → J/(kg·°C) Joule per Kilogram °C → Btu (th) per Pound °R J/(kg·°C) → Btu(th)/(lb·°R) Btu (th) per Pound °R → Joule per Kilogram °C Btu(th)/(lb·°R) → J/(kg·°C) Joule per Kilogram °C → Btu (IT) per Pound °C J/(kg·°C) → Btu(IT)/(lb·°C) Btu (IT) per Pound °C → Joule per Kilogram °C Btu(IT)/(lb·°C) → J/(kg·°C)
Joule per Kilogram °C → CHU per Pound °C J/(kg·°C) → CHU/(lb·°C) CHU per Pound °C → Joule per Kilogram °C CHU/(lb·°C) → J/(kg·°C)

Frequently Asked Questions

Quick answers to common conversion queries

To convert 1 Joule per Kilogram °C to Calorie (IT) per Gram °F, you multiply 1 by the conversion factor. Since 1 Joule per Kilogram °C is approximately 0.000239 Calorie (IT) per Gram °F, the result is 0.000239 Calorie (IT) per Gram °F.

The conversion formula is: Value in Calorie (IT) per Gram °F = Value in Joule per Kilogram °C × (0.000239).
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