Pound-force Foot per Pound °R Joule per Kilogram Kelvin

Convert Pound-force Foot per Pound °R to Joule per Kilogram Kelvin with precision
1 Pound-force Foot per Pound °R = 5.380320 Joule per Kilogram Kelvin

Quick Answer: 1 Pound-force Foot per Pound °R is equal to 5.380320456 Joule per Kilogram Kelvin.

How to Convert Pound-force Foot per Pound °R to Joule per Kilogram Kelvin

To convert Pound-force Foot per Pound °R to Joule per Kilogram Kelvin, multiply the value in Pound-force Foot per Pound °R by the conversion factor 5.38032046.

Conversion Formula
1 Pound-force Foot per Pound °R × 5.380320 = 5.3803 Joule per Kilogram Kelvin

Pound-force Foot per Pound °R to Joule per Kilogram Kelvin Conversion Table

Pound-force Foot per Pound °R Joule per Kilogram Kelvin
0.01 0.0538
0.1 0.5380
1 5.3803
2 10.7606
3 16.1410
5 26.9016
10 53.8032
20 107.6064
50 269.0160
100 538.0320
1000 5,380.3205

Complete list of Pound-force Foot per Pound °R for conversion

Pound-force Foot per Pound °R → Joule per Kilogram Kelvin lbf·ft/(lb·°R) → J/(kg·K) Joule per Kilogram Kelvin → Pound-force Foot per Pound °R J/(kg·K) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Joule per Kilogram °C lbf·ft/(lb·°R) → J/(kg·°C) Joule per Kilogram °C → Pound-force Foot per Pound °R J/(kg·°C) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Joule per Gram °C lbf·ft/(lb·°R) → J/(g·°C) Joule per Gram °C → Pound-force Foot per Pound °R J/(g·°C) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Kilojoule per Kilogram Kelvin lbf·ft/(lb·°R) → kJ/(kg·K) Kilojoule per Kilogram Kelvin → Pound-force Foot per Pound °R kJ/(kg·K) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Kilojoule per Kilogram °C lbf·ft/(lb·°R) → kJ/(kg·°C) Kilojoule per Kilogram °C → Pound-force Foot per Pound °R kJ/(kg·°C) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Calorie (IT) per Gram °C lbf·ft/(lb·°R) → cal(IT)/(g·°C) Calorie (IT) per Gram °C → Pound-force Foot per Pound °R cal(IT)/(g·°C) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Calorie (IT) per Gram °F lbf·ft/(lb·°R) → cal(IT)/(g·°F) Calorie (IT) per Gram °F → Pound-force Foot per Pound °R cal(IT)/(g·°F) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Calorie (th) per Gram °C lbf·ft/(lb·°R) → cal(th)/(g·°C) Calorie (th) per Gram °C → Pound-force Foot per Pound °R cal(th)/(g·°C) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Kilocalorie (IT) per Kilogram °C lbf·ft/(lb·°R) → kcal(IT)/(kg·°C) Kilocalorie (IT) per Kilogram °C → Pound-force Foot per Pound °R kcal(IT)/(kg·°C) → lbf·ft/(lb·°R)
Pound-force Foot per Pound °R → Kilocalorie (th) per Kilogram °C lbf·ft/(lb·°R) → kcal(th)/(kg·°C) Kilocalorie (th) per Kilogram °C → Pound-force Foot per Pound °R kcal(th)/(kg·°C) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Kilocalorie (IT) per Kilogram Kelvin lbf·ft/(lb·°R) → kcal(IT)/(kg·K) Kilocalorie (IT) per Kilogram Kelvin → Pound-force Foot per Pound °R kcal(IT)/(kg·K) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Kilocalorie (th) per Kilogram Kelvin lbf·ft/(lb·°R) → kcal(th)/(kg·K) Kilocalorie (th) per Kilogram Kelvin → Pound-force Foot per Pound °R kcal(th)/(kg·K) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Kilogram-force Meter per Kg K lbf·ft/(lb·°R) → kgf·m/(kg·K) Kilogram-force Meter per Kg K → Pound-force Foot per Pound °R kgf·m/(kg·K) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Btu (IT) per Pound °F lbf·ft/(lb·°R) → Btu(IT)/(lb·°F) Btu (IT) per Pound °F → Pound-force Foot per Pound °R Btu(IT)/(lb·°F) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Btu (th) per Pound °F lbf·ft/(lb·°R) → Btu(th)/(lb·°F) Btu (th) per Pound °F → Pound-force Foot per Pound °R Btu(th)/(lb·°F) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Btu (IT) per Pound °R lbf·ft/(lb·°R) → Btu(IT)/(lb·°R) Btu (IT) per Pound °R → Pound-force Foot per Pound °R Btu(IT)/(lb·°R) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Btu (th) per Pound °R lbf·ft/(lb·°R) → Btu(th)/(lb·°R) Btu (th) per Pound °R → Pound-force Foot per Pound °R Btu(th)/(lb·°R) → lbf·ft/(lb·°R) Pound-force Foot per Pound °R → Btu (IT) per Pound °C lbf·ft/(lb·°R) → Btu(IT)/(lb·°C) Btu (IT) per Pound °C → Pound-force Foot per Pound °R Btu(IT)/(lb·°C) → lbf·ft/(lb·°R)
Pound-force Foot per Pound °R → CHU per Pound °C lbf·ft/(lb·°R) → CHU/(lb·°C) CHU per Pound °C → Pound-force Foot per Pound °R CHU/(lb·°C) → lbf·ft/(lb·°R)

Frequently Asked Questions

Quick answers to common conversion queries

To convert 1 Pound-force Foot per Pound °R to Joule per Kilogram Kelvin, you multiply 1 by the conversion factor. Since 1 Pound-force Foot per Pound °R is approximately 5.380320 Joule per Kilogram Kelvin, the result is 5.380320 Joule per Kilogram Kelvin.

The conversion formula is: Value in Joule per Kilogram Kelvin = Value in Pound-force Foot per Pound °R × (5.380320).
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